E(x)=2(x+3)^2-(2+x)(x-2=-2(5x+7)

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Solution for E(x)=2(x+3)^2-(2+x)(x-2=-2(5x+7) equation: 



(E)=2(E+3)^2-(2+E)(E-2=-2(5E+7)

We move all terms to the left:

(E)-(2(E+3)^2-(2+E)(E-2)=0

We add all the numbers together, and all the variables

E-(2(E+3)^2-(E+2)(E-2)=0

We use the square of the difference formula

E^2+E+4=0

a = 1; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·1·4
Δ = -15
Delta is less than zero, so there is no solution for the equation

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